Question

va rog rezolvaati ecuatia

Answer 1

$2,(3)x+1 \frac{1}{6}=0,(6)x+2 \frac{1}{3} \\ \frac{21}{9}x+ \frac{7}{6}= \frac{6}{9}x+ \frac{7}{3} \\ \frac{21}{9}x- \frac{6}{9}x= ^6/\frac{7}{3}- \frac{7}{6} \\ \frac{15}{9}x= \frac{42-7}{6} \\ x= \frac{35}{6}: \frac{15}{9} \\ x= \frac{35}{6}\cdot \frac{9}{15} \\ x= \frac{7}{2}$