Question

Va rog, rezolvarea completa! Ofer coroana pentru raspuns complet

Answer 1

1 mol Mg contine 6,023*10²³ atomi , iar fiecare atom de Mg are 12 e⁻ , deci 1 mol Mg contine 12*6,023*10²³=72,276*10²³=7,2276*10²⁴ e⁻.Nr de moli de Mg care contin nr de e⁻ specificati in cerinta este :

$\frac{2,4*6,023*10^{24}}{7,2276*10^{24}}=2$


2Mg+O2=2MgO

$V_m=22,4l$

$V_O=22,4l(raspuns \ corect=a)$