Question

va rog rezolvati ex 3 4 dau coroana

Answer 1

3)2^3+2^10÷2^8+2×2^7÷2^6+2^10÷(3×2^5+2^5)-4×2^3
=2^3+2^2+2^2+2^10÷(4×2^5)-4×2^3
=2^3+2^2+2^2+2^10÷(2^2×2^5)-4×2^3
=2^3+2^2+2^2+2^10÷2^7-4×2^3
=2^3+2^2+2^2+2^3-4×2^3
=>1×2^3 +1×2^3 -4×2^3=(1+1-4)×2^3
=-2×2^3 +2×2^2
=-2^4 +2^3
=(-2+1)×2^3
=-1×8
=-8

4)3^87(3^3×3^14)^5 +7×(352-350÷2)
=3^87(3^17)^5 +7(352-175)
=3^87 ×3^85 +7×177
=3^172 +1239

P.S. ^=la putere