Question

Va rog, rezolvati radicalii aia compusi la a! Ms! <3

Answer 1

a=√[6-2√(4+2√3)]-√[8-2√(6+2√5)]=
=√[6-2√(3+2√3+1)]-√[8-2√(5+2√5+1)]=
=√[6-2√(√3+1)²]-√[8-2√(√5+1)²]=
=√[6-2(√3+1)]-√[8-2(√5+1)]=
=√(6-2√3-2)-√(8-2√5-2)=
=√(4-2√3)-√(6-2√5)=
=√(4-√12)-√(6-√20)=
=√[4+√(16-12)]/2-√[4-√(16-12]/2-{√[6+√(36-20)]/2-√[6-√(36-20)]/2}=
=√(4+√4)/2-√(4-√4)/2-√(6+√16)/2+√(6-√16)/2}=
=√(4+2)/2-√(4-2)/2-√(6+4)/2+√(6-4)/2}=
=√3-√1-√5+√1=
=√3-√5