Question

Va rog sa ama ajutati..

Answer 1

daca x∈(-∞,1/2) avem
-(2x-1)≤3
-2x+1≤3
2x≥2
x≥1 nu are solutie
daca x∈(1/2,+∞)
2x-1≤3
2x≤4
x≤2 
solutie
A={1,2}

la B
-1≤2-x
x≤3 x={1,2,3}
2-x≤5
x≥3 ,x∈(3,+∞)
B={1,2,3,4........+∞}
A∧B={1,2,}