Question

va rog sa ma ajuati DMNAJ (3x+4)la patrat=(2x+1)la patrat

Answer 1

$(3x+4)^2=(2x+1)^2 \\\\ 9x^2+24x+16=4x^2+4x+1 \\\\ 9x^2-4x^2+24x-4x+16-1=0 \\\\ 5x^2+20x+15=0 \ \ \ |:5 \\\\ x^2+4x+3=0 \\\\ x^2+x+3x+3=0 \\\\ x(x+1)+3(x+1)=0 \\\\ (x+1)(x+3)=0 \\\\ x+1=0 \ \ \ \And \ \ \ x+3=0 \\\\ \boxed{x=-1} \ \ \ \ \ \ \ \ \ \boxed{x=-3}\\\\\\\boxed{\boxed{S\in \{-1;-3\}}}$