Question

Vă rog să mă ajutați!​

Answer 1

Răspuns:

Explicație pas cu pas:

a) -2(x-3)+3(2-x) = x <=> -2x+6+6-3x-x = 0 =>

-6x = -12 => x = (-12):(-6) => x = 2

b) 3(x+2)-5(x-1) = 3-6x <=> 3x+6-5x+5 = 3-6x =>

-2x+6x = 3-11 => 4x = -8 => x = -8:4 => x = -2

c) 3x-5(x+√2) = √2-4x => 3x-5x-5√2 = √2-4x =>

-2x+4x = √2+5√2 => 2x = 6√2 => x = 3√2

d) (2x+1)(√2+1) = 7√3(√2+1) =>

2x+1 = 7√3 => 2x = 7√3-1 => x = (7√3-1)/2

e) ⁶⁾(x+3)/2 + ³⁾(x-2)/4 = ²⁾5/6 =>

6x+18+3x-6 = 10 => 9x = 10-12 => x = -2/9

f) (2x-3)/8 - ²⁾(3x-2)/4 = ⁴⁾(x+1)/2 =>

2x-3-6x+4 = 4x+4 => -4x-4x = 4-1 => -8x = 3 =>

x = -3/8

g) ²⁾(5x+1)/3 - (2x-1)/6 +³⁾3x/2 = ⁶⁾1 =>

10x+2-2x+1+9x = 6 => 17x = 3 => x = 3/17

h) ²⁾(x+2)/5 - (x-2)/10 + ⁵⁾(2x-3)/2 = ¹⁰⁾x =>

2x+4-x+2+10x-15 = 10x => x = 9