Question

Va rog sa ma ajutati!!!

Answer 1

19.∡ABC=180°-∡ABD=180°-130°=50°

∡ACB=180°-∡ACE=180°-150°=30°

IN ΔABC→∡BAC=180°-∡ABC-∡ACB=180°-50°-30°=100°

20. ∡A/4=∡B/6=∡C/8=X

∡A=4X;∡B=6X;∡C=8X

∡A+∡B+∡C=180°

4X+6X+8X=180°

18X=180°→X=10°

∡A=40°;∡B=60°;∡C=80°

21 NU AM CUM, TREBUIE DESEN