Question

va rog sa ma ajutati

Answer 1

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Answer 2

$\frac{2x - 1}{3x - 2} = \frac{4x + 3}{6x + 5} \\ \\ (2x - 1)(6x + 5) = (4x + 3)(3x - 2) \\ \\ {12x}^{2} + 10x - 6x - 5 = {12x}^{2} - 8x + 9x - 6 \\ \\ {12x}^{2} + 4x - 5 = {12x}^{2} + x - 6 \\ \\ 4x - 5 = x - 6 \\ \\ 4x - 5 - x = - 6 \\ \\ 3x - 5 = - 6 \\ \\ 3x = - 6 + 5 = - 1 \\ \\ x = - \frac{1}{3}$