Question

Va rog sa ma ajutati!!!​

Answer 1

-se foloseste relatia :

n = m : M     ;   n=nr.moli  ; m=masa subst. (g ) ;   M =masa molara (g/moli )

a.

2,5 moli oxigen

m= n . M

m=2,5 moli . 32 g/moli=80 g oxigen

b.

5 moli  iod                     [ M I 2=2 .127=254 ----->254g/moli ]

m= 5moli . 254 g/moli = 1270 g iod

c.

0,5 kmoli HNO3

m= 0,5 kmoli . 63 kg/kmoli=31,5 kg HNO3= 31500 g HNO3

MHNO3=1+ 14 +3.16=63-----> 63kg/kmoli

d.

3 kmoli CaO

M=40+16=56----->56kg/kmoli

m=3 kmoli .56kg/kmoli=168 kg CaO

e.

10 moli Na2CO3

M=2.23 +12 +3.16=106------>106g/moli

m= 10moli. 106g/moli=1060 g Na2CO3