Question

va rog sa ma ajutati... cum descompun in factori:
16(x+1)^2-9(x+3)^2

Answer 1

16*(x+1)^2-9*(x+3)^2=(x-5)*(7x+13)
Sper ca te-am ajutat!

Answer 2

$16(x+1)^2-9(x+3)^2= \\ 4^2(x+1)^2-3^2(x+3)^2= \\ \[[4(x+1)]^2-\[[3(x+3)]^2= \\ \[[4(x+1)-3(x+3)][4(x+1)+3(x+3)]$


Formule folosite:

$a^m\cdot b^m=(a\cdot b)^m \\ a^2-b^2=(a+b)(a-b)$