Question

Va rog sa ma ajutati.
Dau coroana.

Answer 1

$3*2^{10} + 3*2^{11} = 3*2^{10}(1+2) = 3*3*2^{10} = 3^{2} * (2^{5}) ^{2} = (3*2^{5} )^{2} = (3*32)^{2} = 96^{2} (P.p)$

Answer 2

$3*2^{10}+3*2^{11} =3*2^{10}(1+2)=3^{2}*2^{10}=(3*2^{5})^{2}= 96^{2}$ deci numarul este patrat perfect