Question

VA ROG SA MA AJUTATI. EXERCIȚIILE 20 SI 21.DAU COROANA!!!!!!!!!!!!!!

Answer 1

Rezolvarea se află în atașamente.

Answer 2

20. a) 8(√6+√2)/4 - 5(√6-1)/5 - 5(√2+1)/1 - 4(√6-√2)/4 =  simplificam

2(√6+√2) - (√6-1) - 5(√2+1)- (√6-√2) =

2√6+2√2-√6+1-5√2-5-√6+√2 = - 3√2  - 4

b) 5(√3+√2)-20(2√3+√2)/10+30(3√2-√3)/15+4(√3+1)/2+2(√2-1) = simplificam

5(√3+√2)-2(2√3+√2)+2(3√2-√3)+2(√3+1)+2(√2-1) =

5√3+5√2-4√3-2√2+6√2-2√3+2√3+2+2√2-2 = 11√2+√3

c) 2√2(√2+1)+3√3(√3-1)+4√6(√3-√2)+√6(2√3-3√2)/3 -√6(√3+√2) = aducem la acelasi numitor ... 3... =

[6√2(√2+1)+9√3(√3-1)+12√6(√3-√2)+√6(2√3-3√2) -3√6(√3+√2)]/3 =

(12+6√2+27-9√3+36√2-24√3+6√2-6√2-9√2-6√3)/3 =

(39+33√2-39√3)/3 = 13+11√2-13√3

d) 2√3(3√3+5)/22 - 6√3(2√3-3)/9 + 3√3(2√3+3)/9 - 4√3(√3-2) = simplificam

√3(3√3+5)/11 - 2√3(2√3-3)/3 + √3(2√3+3)/3 - 4√3(√3-2) = aducem la acelasi numitor 33 =

[3√3(3√3+5) - 22√3(2√3-3) + 11√3(2√3+3)/3 - 132√3(√3-2)]/33 =

(27+15√3-132+66√3+66+33√3-396+264√3)/33 =

( - 435+378√3)/33 = ( - 145+126√3)/11