Va rog sa ma ajutati la 3 si 4.Multumesc!
Anexe:
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Răspunsuri la întrebare
Răspuns de
3
Rezolvarea se află în poze.
Anexe:
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Răspuns de
1
3 )
a )

b )

4 )
a )

b )

c )

d )

a )
b )
4 )
a )
b )
c )
d )
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