Matematică, întrebare adresată de Usercristi59, 8 ani în urmă

Va rog sa ma ajutati la 3 si 4.Multumesc!

Anexe:

Răspunsuri la întrebare

Răspuns de augustindevian
3
Rezolvarea se află în poze.
Anexe:
Răspuns de Utilizator anonim
1
3 )



a )




( \dfrac{13}{40}  +  \dfrac{3}{15} +  \dfrac{7}{30}  ) + ( \dfrac{7}{40}  +  \dfrac{3}{30}  +  \dfrac{2}{15} ) =  \\  \\ \\  ( \dfrac{13}{40}  +  \dfrac{7}{40} ) + ( \dfrac{3}{15}  +  \dfrac{2}{15} ) + ( \dfrac{7}{30}  +  \dfrac{3}{30} ) =  \\  \\  \\  \dfrac{20}{40}^{ \div 20} +  \dfrac{5}{15}^{ \div 5}   +  \dfrac{10}{30}^{ \div 10}  =  \\  \\  \\  \dfrac{1}{2}^{ \times 3}   +  \dfrac{1}{3}^{ \times 2}  +  \dfrac{1}{3}^{ \times 2}  =  \\  \\  \\  \dfrac{3}{6}  +  \dfrac{2}{6}  +  \dfrac{2}{6}  =  \dfrac{7}{6}




b )




( 2\dfrac{1}{14}  + 1 \dfrac{3}{7}) + ( \dfrac{5}{4}   +  \dfrac{6}{14}) + ( \dfrac{4}{7}^{ \times 2}   +  \dfrac{7}{4}) =  \\  \\  \\ ( \dfrac{29}{14}  +  \dfrac{10}{7} ^{ \times 2}  ) +( \dfrac{5}{4}  +  \dfrac{6}{14} ) + ( \dfrac{8}{14}  +  \dfrac{7}{4} ) =  \\  \\  \\ \dfrac{29 +20 +  6 + 8}{14}  + \dfrac{5 + 7}{4}   =  \\  \\  \\  \dfrac{63}{14}^{ \div 7}  +  \dfrac{12}{4}^{ \div 4}  =  \\  \\  \\  \dfrac{9}{2}  +  \dfrac{3}{1}^{ \times 2}  =  \dfrac{9}{2}  +  \dfrac{6}{2}  =  \dfrac{15}{2}







4 )





a )




 \dfrac{56}{55}^{ \times 64}  ( > ) \dfrac{65}{64}^{ \times 55} \\  \\ \\  \dfrac{3584}{3520}   ( > ) \dfrac{3575}{3520}




b )





 \dfrac{68}{66}^{ \times 76}  (  > ) \dfrac{78}{76}^{ \times 66}  \\  \\  \\  \dfrac{5168}{5016}  ( > ) \dfrac{5148}{5016}






c )







 \dfrac{124}{123}^{ (141}  ( > ) \dfrac{142}{141}^{(123}   \\  \\  \\ \dfrac{17484}{17343}  ( > ) \dfrac{17466}{17343}






d )





 \dfrac{2012}{2011}^{(2012}  () \dfrac{2013}{2012} ^{(2011}  \\  \\  \\  2012 \times 2012  \neq 2011 \times 2013 \\  \\ \\  4048144\neq4048143  \\  \\  \\  \dfrac{4048144}{4046132} ( > ) \dfrac{4048143}{4046132}




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