Question

Va rog sa ma ajutati la a si la b!

Answer 1

$arcsin \frac{1}{2} + arccos \frac{ \sqrt{3} }{2} = \frac{\pi}{6} + \frac{\pi}{6} = \frac{2\pi}{6} = \frac{\pi}{3} \\ arcsin( - \frac{ \sqrt{3} }{2} ) + arsin1 = \frac{4\pi}{3} + \frac{\pi}{2} = \frac{12\pi}{6} = 2\pi$