Question

va rog sa ma ajutati n²-3/n-3 ∈Z
aflatil pe n

Answer 1

n²-3/n-3∈Z⇒
n²-3=n-3⇒n²-n-3+3=0⇒n²-n=0
a=1
b=-1
c=0
Δ=b²-4ac⇒(-1)²-4×1×0⇒1+0⇒Δ=1⇒√Δ=√1⇒Δ=1
n1n2=-b+-√Δ/2a=
n1=1+1/2⇒2/2⇒n1=1
n2=1-1/2⇒0/2⇒n2=0
n∈Z
sucees