Question

Va rog sa rezolvati problema 57!!Dau coroana!

Answer 1

X= traseul

1.e.
3/10*x; restul traseului este de 7/10*x

2.e.
1/7*7/10x=  1/10x

3.e.
1/2*x+20= x/2+20

a) 3/10x+1/10x+1/2x+20= x
4x/10+5x/10+200/10= 10x/10
9x+200= 10x
200=10x-x
x=200 km

b)
3/10*200= 60km
1/10*200=20km
200/2+20=120km

c)120 km..........100%
 60 km...............x%
x=60*100:120= 50%