Question

Vă rog tare mult de tot.......Dau coroană la cel mai bun răspuns.....!!

Answer 1

a) $\frac{10x+3}{3}+\frac{1-3x}{5} = \frac{8x+4}{3}+ \frac{1}{5}$ / *15

5(10x+3)+3(1-3x) = 5(8x+4) +3

50x+15+3-9x = 40x+20+3

50x+15-9x = 40x+20

41x+15 = 40x+20

41x-40x = 20-15

x = 5

b) $\frac{5x-7}{10} +\frac{2x+17}{15} = \frac{3x-4}{16} +1\frac{7}{30} =\\\\1\frac{7}{30}= \frac{37}{30}\\\\\frac{5x-7}{10} +\frac{2x+17}{15} = \frac{3x-4}{16} +\frac{37}{30} / *240$

24(5x-7)+16(2x+17) = 15(3x-4)+296

120x-168+32x+272 = 45x-60+296

152x-45x = 236-104

107x = 132

x = $\frac{132}{107}$