Question

Vă rogg!
E urgent!!!​

Answer 1

Răspuns:

Explicație pas cu pas:

a) (2/3)⁵·(2/3)⁷ = (2/3)⁵⁺⁷ = (2/3)¹²

b) (3/10)³·(3/10)¹⁰ = (3/10)³⁺¹⁰ = (3/10)¹³

c) (11/5)⁴·(11/5)⁶ = (11/5)⁴⁺⁶ = (11/5)¹⁰

d) (3/4)¹¹:(3/4)⁴ = (3/4)¹¹⁻⁴ = (3/4)⁷

e) (8/3)⁹:(8/3)⁸ = (8/3)⁹⁻⁸ = 8/3

f) (13/17)²²:(13/17)²⁰ = (13/17)²²⁻²⁰ = (13/17)² = 169/289

g) [(2/5)⁵]¹¹ = (2/5)⁵ˣ¹¹ = (2/5)⁵⁵

h) [(14/27)⁶]⁴ = (14/27)⁶ˣ⁴ = (14/27)²⁴

i) [(3/100)⁰]²⁰¹⁹= (3/100)⁰ˣ²⁰¹⁹ = (3/100)⁰ = 1

sau [(3/100)⁰]²⁰¹⁹= 1²⁰¹⁹ = 1

Am folosit formulele :

aⁿ·aᵇ = aⁿ⁺ᵇ

aⁿ:aᵇ = aⁿ⁻ᵇ

(aⁿ)ᵇ = aⁿˣᵇ

a⁰ = 1

1ⁿ = 1