Question

va rogg. e urgentt. am nevoiee​

Answer 1

Explicație pas cu pas:

a)

11 | A => 11 | 3×A <=> 11 | 3×(2a + 5b) => 11 | (6a + 15b) => 11 | (6a + 4b + 11b) => 11 | [2×(3a + 2b) + 11b]

11 | 11 b => 11 | 2×(3a + 2b) => 11 | (3a + 2b)

<=> 11 | B

.

11 | B => 11 | 2×B <=> 11 | 2×(3a + 2b) => 11 | (6a + 4b) <=> 11 | [(6a + 4b) + 11b] => 11 | (6a + 15b) => 11 | 3×(2a + 5b) => 11 | 3×A

<=> 11 | A

b)

31 | (5a + 7b) <=> 31 | 8×(5a + 7b) => 31 | (40a + 56b) => 31 | [5×(8a + 5b) + 31b)]

31 | 31b => 31 | 5×(8a + 5b)

<=> 31 | (8a + 5b)

q.e.d.