Question

va roggggg r urgent......

Answer 1

$y(y - 2) = y + 4 \\ {y}^{2} -2 y - y - 4 = 0 \\ {y}^{2} - 3y - 4 = 0 \\ delta = 9 - 4 \times 1 \times ( - 4) = 2 \\ y1 = 3 + 5 \div 2 = 4 \\ y2 = 3 - 5 \div 2 = - 1$
caz 1. y=4 => 4(x+2)=x-2 => 4x+8=x-2
3x=-10. x= -3,(3)

caz 2. y= -1 => -1(x+2)=x-2 =>-x-2=x-2. =>2x=0
x=0