Question

Va roggggg repede,nu stiu sa fac nimic de aici,ne-a dat cu totul altceva fata de ce a predat in clasa!Macar un ex daca se poate...dau coroana!!!​

Answer 1

Explicație pas cu pas:

sper ca te am ajutat paa

pupiciiii

Answer 2

reguli de calcul cu puteri:

$\boxed {a^{m} \cdot a^{n} = a^{m + n}}$   $\boxed {a^{m} : a^{n} = a^{m - n}}$

$\boxed {\Big(a^{m}\Big)^{n} = a^{m \cdot n}}$

a)

$\bigg(\dfrac{7}{5}\bigg)^{8} \cdot \bigg(\dfrac{7}{5}\bigg)^{1} : \bigg(\dfrac{7}{5}\bigg)^{7} - \bigg(\dfrac{13}{10}\bigg)^{2} =$

$= \bigg(\dfrac{7}{5}\bigg)^{8+1-7} - \dfrac{13^{2}}{10^{2}} = \bigg(\dfrac{7}{5}\bigg)^{2} - \dfrac{169}{100}$

$= \dfrac{7^{2}}{5^{2}} - \dfrac{169}{100} = \dfrac{^{4)}49}{25} - \dfrac{169}{100}$

$= \dfrac{196-169}{100} =\bf \dfrac{27}{100}$

f)

$\bigg[\bigg(\dfrac{18}{5}\bigg)^{7}\bigg]^{9} : \bigg[\bigg(\dfrac{18}{5}\bigg)^{5}\bigg]^{12} : \bigg(\dfrac{36^{(2}}{10}\bigg) - \bigg(\dfrac{7}{5}\bigg)^{2} =$

$= \bigg(\dfrac{18}{5}\bigg)^{7\cdot9} : \bigg(\dfrac{18}{5}\bigg)^{5 \cdot 12} : \bigg(\dfrac{18}{5}\bigg) - \dfrac{7^{2}}{5^{2}}$

$= \bigg(\dfrac{18}{5}\bigg)^{63} : \bigg(\dfrac{18}{5}\bigg)^{60} : \bigg(\dfrac{18}{5}\bigg)^{1} - \dfrac{49}{25}$

$= \bigg(\dfrac{18}{5}\bigg)^{63-60-1} - \dfrac{49}{25} = \bigg(\dfrac{18}{5}\bigg)^{2} - \dfrac{49}{25}$

$= \dfrac{324}{25} - \dfrac{49}{25} = \dfrac{324 - 49}{25} = \dfrac{275}{25} = \bf 11$