Matematică, întrebare adresată de Desteapta200715, 8 ani în urmă

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Anexe:

Răspunsuri la întrebare

Răspuns de pav38
5

\Big[\dfrac{8}{35} +\Big[\Big(\dfrac{3}{2}-\dfrac{33}{35} \Big)+ \Big(\dfrac{3}{14}-\dfrac{2}{35} \Big)-\Big(2-\dfrac{12}{7}+\dfrac{5}{14}\Big)\Big]\Big]\cdot\dfrac{1}{(0,3)^{1}}\\\\\\\Big[\dfrac{8}{35}+\Big[\Big(\dfrac{35\cdot3-33\cdot2}{70}\Big)+ \Big(\dfrac{3\cdot5-2\cdot2}{70}\Big)-\Big(\dfrac{2\cdot70-12\cdot10+5\cdot5}{70}\Big)\Big]\Big]\cdot\dfrac{1}{\dfrac{3}{10}}\\\\\\\Big[\dfrac{8}{35}+\Big(\dfrac{39}{70}+\dfrac{11}{70}-\dfrac{45}{70}\Big)\Big]\cdot\dfrac{1}{1}\cdot\dfrac{10}{3}

\Big(\dfrac{8}{35}+\dfrac{5}{70}\Big)\cdot\dfrac{10}{3}=\\\\\\\dfrac{8\cdot2+5}{70}\cdot\dfrac{10}{3}=\\\\\\\dfrac{21}{70}\cdot\dfrac{10}{3}=\\\\\\\dfrac{210}{210}=\\\\\\\boxed{1}

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