Question

Va roog! <3 am nevoie urgenta!

Answer 1

2.  $a) \frac{12}{3 \sqrt{3}} = \frac{4}{ \sqrt{3}}= \frac{4 \sqrt{3}}{3}$
$b) \frac{21}{ \sqrt{14}} = \frac{21 \sqrt{14}}{14} = \frac{3 \sqrt{14}}{2}$
$c) - \frac{28}{4 \sqrt{7}} =- \frac{14}{2 \sqrt{7}} =- \frac{7}{ \sqrt{7}} =- \frac{7 \sqrt{7}}{7} =- \sqrt{7}$
$d) \frac{ \sqrt{2}}{ \sqrt{3}} = \frac{ \sqrt{6}}{3}$
$e) \frac{ \sqrt{6}}{2 \sqrt{2}} = \frac{ \sqrt{12}}{4} = \frac{2 \sqrt{3}}{4} = \frac{ \sqrt{3}}{2}$
$f) \frac{5 \sqrt{3}}{4 \sqrt{5}} = \frac{5 \sqrt{15}}{20} = \frac{ \sqrt{15}}{4}$
3.$\frac{12}{\sqrt{2}} - \frac{14}{ \sqrt{8}} + \frac{16}{ \sqrt{32}} - \frac{18}{3 \sqrt{2}} =$$\frac{12 \sqrt{4}}{ \sqrt{8}} - \frac{14}{ \sqrt{8}}+ \frac{16}{ \sqrt{32}} - \frac{18}{3 \sqrt{2}}$

Answer 2

Cu ce sa te ajut? Nu văd problema.