Question

Va roog mult de tot ex 9 va rog urgeent

Answer 1

   
[tex]\displaystyle \\ a) \\ l_6 = 12~cm \\ R = l = \boxed{12~cm} \\ a_6 = \frac{l \sqrt{3} }{2} =\frac{12\sqrt{3} }{2}=\boxed{6\sqrt{3}~cm} \\ \\ \\ b) \\ l_6 = 4\sqrt{3}~cm \\ R = l = \boxed{4\sqrt{3}~cm} \\ a_6 = \frac{l \sqrt{3} }{2} =\frac{4\sqrt{3}\times\sqrt{3} }{2} =\frac{4\times3 }{2} = \boxed{6 ~cm}\\ \\ \\ c) \\ l_6 = x~cm \\ R = l = \boxed{x~cm} \\ a_6 = \frac{l \sqrt{3} }{2} =\boxed{\frac{x\sqrt{3} }{2} ~cm}[/tex]