Question

Va roog!!Problema din pozaa!!Repede!!
Sau coronița!!

Answer 1

[tex]\it B = \left[\dfrac{1}{2}\left(\dfrac{1}{3} +\dfrac{1}{5}+\dfrac{1}{7}+\dfrac{1}{9}\right)\right]^4 = \left(\dfrac{1}{2}\right)^4 \left(\dfrac{1}{3} +\dfrac{1}{5}+\dfrac{1}{7}+\dfrac{1}{9}\right)^4 = \\\;\\ \\\;\\ =\dfrac{1}{2^4}\cdot A [/tex]

$\it \dfrac{A}{B} = \dfrac{A}{\dfrac{1}{2^4}\cdot A} = \dfrac{1}{\dfrac{1}{2^4}}=1:\dfrac{1}{2^4} =1\cdot\dfrac{2^4}{1} = 2^4$