Question

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Answer 1

5.

a) AD^2=AB^2-BD^2

AD^2=5^2-3^2

AD^2=16

AD=4 [cm]

/\PAT~/\CDA

=>PT=PD=3x,PA=5x,AT=4x

AD=5x+3x=4

8x=4

x=0,5

3x=1,5 [cm]

6.

a)

AB=AA'=120/12 =10 [cm]

A'B^2= 100+100=200

A'B=BC'=C'A'

A_A'BC'= (A'B^2·rad. din 3)/4=200/4·rd. din 3=50·rad. din 3 [cm^]

b)

AS>10

ST>=10

TM>=10

sau

AS>=10

ST>=10

TM>10

sau

AS>=10

ST>10

TM>=10

sau

AS>10

ST>10

TM>10

=>

AS+ST+TM>30 [cm]