Question

va rooooog mult ajutati-ma la oricare din ele.....va rooooooog urgent

Answer 1

AM/AB=AN/AC=MN/BC

3/8=AN/7=MN/9
AN=21/8
MN=27/8
P(AMN)=3+21/8+27/8=3+48/8=3+6=9 cm


L=40
notam a inaltimea triunghiul cu aria de 15    ⇒a=2*15/40=30/40
notam b inaltimea triunghiul cu aria de 10   ⇒b=2*10/40=20/40
inaltimea dreptunghiului =a+b=30/40+20/40=50/40=1,25
Adreptunghi=40×1,25=50 cm
A(x)=50-(15+5+10)=20 cm²

Answer 2

fie h1 si h2 inaltimile treiunghiurilor de arii 15 si respectiv, 10
atunci


40 *h1/2+40*h2/2=15+10

40 * latime/2=15+10=25
40*latime=50
latime =50:40=1,25

arie dreptunghi =40*1,25=50
50=15+5+10+x=30+x
x=20


prima problema
3/8=AB/7=MN/9
⇒AB=21/8 si MN=27/8
Perim AMN=3+3/8+27/8=3+30/8=3+15/4=12/4+15/4=27/4