Question

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Answer 1

Răspuns:

$\frac{ {a}^{2} + {b}^{2} }{a + b} \geqslant \frac{a + b}{2}$

$( {a}^{2} + {b}^{2} ) \times 2 \geqslant {(a + b)}^{2}$

$2 \times {a}^{2} + 2 \times {b}^{2} \geqslant {a}^{2} + 2 \times a \times b + {b}^{2}$

${a}^{2} + {b }^{2} - 2ab \geqslant 0$

${(a - b)}^{2} \geqslant 0 = > a.b > 0$