Question

valoarea calculului (√2-√3) patrat -(√3-2)(√3+2)+2√6 este egal cu

Answer 1

$( \sqrt{2} - \sqrt{3} )^2-( \sqrt{3} -2)( \sqrt{3} +2)+2 \sqrt{6} = \\ = \sqrt{2^2} -2 \cdot \sqrt{2} \cdot \sqrt{3} + \sqrt{3^2} -3+4+2 \sqrt{6} = \\ =2-2 \sqrt{6} +3-3+4+2 \sqrt{6} = \\ =2+3-3+4= \\ =5-3+4= \\ =2+4= \\ =\boxed{6}$