Question

valorile intregi ale lui 'a' pentru care ecuatia 3ax-5a=x+11 are solutie numar intreg sunt:
a. 1; 13
b 0; 1; 13
c. -6; 0; 1; 13
d.-6; 1; 13

Answer 1

a. 

a=1

3x1-5x1=x+11
3-5=x+11
-2=x+11
x=11+2
x=13

a=13

13x3-13x5=x+11
39-65=x+11
-26=x+11
x=11+26
x=37