Question

Valorile reale ale lui x care verifica ecuatia x la a doua+5x+6=0 sunt x1=... si x2=...

Answer 1

a=1
b=5
c=6
=>delta=b^2-4*a*c=5^2-4*1*6=25-24=1
x1=-b+radical din delta/2*a
x1=-5+radical din 1/2*1
x1=-5+1/2
x1=-4/2
x1=-2

x2=-b-radical din delta/2*a
x2=-5-1/2*1
x2=-6/2
x2=-3

Answer 2

x^2+5x+6=0
->> x^2+3x+2x+6=0
->> x(x+3)+2(x+3)=0
(x+3)(x+2)=0
->> x+3 = 0 ->> x1=0-3=-3 ( corect ) daca x= -3 ecuatia da 0
sau x+2 = 0 ->>> x2= 0-2=-2 ( corect ) daca x = -2 ecuatia da 0
Bafta sper ca te-am ajutat !!!