Question

Varog foarte mult!!!! Dau coroana

Answer 1

[tex]a) 20+3x=59 =\ \textgreater \ 59-20=3x =\ \textgreater \ x= \frac{39}{3}=13; [/tex]
$b) 32x-28=30x+12+404; 32x-30x=416+28; 2x=444; x=222$
$c)43+49-6x=32=\ \textgreater \ 92-6x=32=\ \textgreater \ 6x=60 = \ \textgreater \ x=10;$
[tex]d) 7*{2+6*[20-3*(33-27)]}+x=2109; 7*[2+6*(20-3*6)]+x=2109=> 7*[2+6*(20-18)]+x=2109 => 7*[2+(6*2)]+x=2109 => 7*{2+12)+x=2109 =>  7*14+x=2109 = > 98+x=2109 => x=2109-98=2011[/tex]
$e)10*[x-10*(216+300)]=1000 => 10*(x-5160)=1000 => 10x-51600=1000=> 10x= 50600 => x=5060;$
$f)84x+9*[1+2*(3+4*2)]=80x+220+227=>84x+9*23=80x+447 = >84x+207=80x+447 => 84x-80x = 447-207 = > 4x=240 => x=60;$