Question

ve rog C si D am nevoieeee plzzzz​

Answer 1

Răspuns:

Explicație pas cu pas:

Answer 2

Răspuns:

Explicație pas cu pas:

c.) x=$72\sqrt{6} (\frac{1}{2\sqrt{2} }-\frac{1}{4\sqrt{2} } )$

   y=$\sqrt{3}+\frac{1-\sqrt{3} }{3-\sqrt{3} }$

Mg=$\sqrt{x*y}$

Vom calcula x si y, pe rand, pentru a simplifica calculele:

x=$72\sqrt{6}(\frac{2}{4\sqrt{2} }-\frac{1}{4\sqrt{2} } ) =72\sqrt{6} *\frac{1}{4\sqrt{2} } =\frac{72*\sqrt{2}*\sqrt{3} }{4\sqrt{2} }=18\sqrt{3}$

y=$\sqrt{3}+\frac{(1-\sqrt{3} )(3+\sqrt{3} )}{(3+\sqrt{3} )(3-\sqrt{3} )} =\sqrt{3} +\frac{3+\sqrt{3}-3\sqrt{3}-3 }{9-3} =\sqrt{3} +\frac{-2\sqrt{3} }{6}=\sqrt{3}-\frac{\sqrt{3} }{3} =\frac{3\sqrt{3} }{3} -\frac{\sqrt{3} }{3} =\frac{2\sqrt{3} }{3}$

Mg=$\sqrt{18\sqrt{3}*\frac{2\sqrt{3} }{3} }=\sqrt{6\sqrt{3}*2\sqrt{3} }=\sqrt{12*3}=\sqrt{12}*\sqrt{3} =2\sqrt{3}*\sqrt{3}=2*3=6$

d.)

$x=|\sqrt{11}-4 |+\frac{5}{4-\sqrt{11} } => \\x=|\sqrt{11}-4 |+\frac{5(4+\sqrt{11} )}{(4-\sqrt{11} )(4+\sqrt{11} )} =>\\x=|\sqrt{11}-4 |+\frac{20+5\sqrt{11} }{16-11} =>\\x=|\sqrt{11}-4 |+ \frac{5(4+\sqrt{11} )}{5} => \\x=|\sqrt{11}-4 |+4+\sqrt{11} \\Explicitez \ modulul: \\|\sqrt{11}-4 |=\sqrt{11}-4,daca\ \sqrt{11}-4>0\\ sau \\-(\sqrt{11}-4 ) \ daca \sqrt{11}-4<0\\Presupun \ ca: \\\sqrt{11}-4<0<=> \sqrt{11} <4 <=>11<16\ A=> \\Presupunerea \ facuta \ este \ adevarata=>$

$\sqrt{11}-4<0=> |\sqrt{11}-4 |=-(\sqrt{11}-4 ) =4-\sqrt{11}=> \\x=4-\sqrt{11}+4+\sqrt{11}=4+4=8=> x=8$

$y=|2\sqrt{2}-3 |-\frac{1}{3-2\sqrt{2} } +\sqrt{32}+\sqrt{(-8)^{2} } \\\frac{1}{3-2\sqrt{2} } =\frac{3+2\sqrt{2} }{(3-2\sqrt{2} )(3+2\sqrt{2} )} =\frac{3+2\sqrt{2} }{9-8}=\frac{3+2\sqrt{2} }{1}=3+2\sqrt{2}\\\sqrt{32}=4\sqrt{2} \\\sqrt{(-8)^{2} }=|-8|=8\\Deci, \\y=|2\sqrt{2}-3|-(3+2\sqrt{2} )+ 4\sqrt{2}+8=>\\y=|2\sqrt{2}-3 |-3-2\sqrt{2} +4\sqrt{2}+8=>\\y=|2\sqrt{2}-3 |+2\sqrt{2}+5\\Explicitez \ modulul: \\|2\sqrt{2}-3 |=2\sqrt{2}-3, daca \ 2\sqrt{2}-3>0\\sau \\\\-(2\sqrt{2}-3 ), daca$$2\sqrt{2}-3<0$

$Presupunem \ ca: \\2\sqrt{2}-3>0<=> 2\sqrt{2}>3<=> 8>9 \ F=>\\Presupunerea \ facuta \ este \ falsa=> 2\sqrt{2}-3<0=> |2\sqrt{2}-3 | =-(2\sqrt{2} -3) =3-2\sqrt{2}\\Deci, \\y=3-2\sqrt{2} +2\sqrt{2}+5=8\\Mg=\sqrt{x*y}=\sqrt{8*8}=\sqrt{64} =8$