Question

Voi scrie in cuvinte : patru minus x la puterea a doua supra doi x minus 10 (totul) inmultit cu doi x la puterea a dua minus 20x plus 50 supra x la puterea a doua plus x minus 6

Answer 1

[(4-x²)/(2x-10)]·[(2x²-20x+50)/(x²+x-6)]=
[(2-x)(2+x)/2(x-5)]·[(x-5)(x-5)/(x-2)(x+3)]=simplif cu x-5=
[-(x-2)(x+2)/2]·[(x-5)/(x-2)(x+3)]=simplif cu x-2=
[-(x+2)/2]·[(x-5)/(x+3)=
(-x-2)(x-5)/2(x+3)
cond:x≠-3
-x-2=0
-x=2       ·(-1)
x₁=-2
x-5=0
x₂=5
x∈{-2,5}