Question

Vreau si eu repede descompunerea in produs de factori ireductibili a: (x la puterea 2) -4x-5. Dar nu facuta cu ecuatia de gradul 2!

Answer 1

$x^{2} -4x-5 = x^{2} +x-5x-5=x(x+1)-5(x+1)=(x-5)(x+1)$

Answer 2

[tex] x^{2} -4x-5=0 a=1 b=-4 c=-5 delta = (-4)^{2} -4*1*(-5)=16+20=36 x_{1}= \frac{4+6}{2}=5 x_{2}= \frac{4-6}{2} = \frac{-2}{2}=-1 [/tex]


REZULTATUL FINAL ESTE

(X-5)(X+1)