Question

(x-1)^2<=9 ajutoooor

Answer 1

$x^{2} -2x+1 \leq 9$
Scriem ecuatia atasata:
[tex] x^{2} -2x-8=0 [/tex]
Δ=b^2-4ac
Δ=4 - 32
Δ=36=$6^{2}$
x1=4
x2=-2
Facem tabelul si obtinem: x∈[-2,4] 

Answer 2

$(x-1)^2\leq9\Big|\sqrt{} \\ \\ \sqrt{(x-1)^2}\leq \sqrt9 \\ \\ |x-1|\leq 3 \\ \\ -3\leq x-1\leq 3 \Big|+1 \\ \\ -2\leq x\leq 4 \\ \\ \Rightarrow \boxed{x\in [-2,4]}$


$\\ Stim faptul ca \sqrt{u^2}=|u|.$