Question

X+  1    + √3 = x-2    x∈R
√3+2

Answer 1

Aducem la acelasi numitor si obtinem:

$x+1+3+2\sqrt3=x\sqrt3+2x-2\sqrt3-4$

Trecem termenii cu x in dreapta:

$4\sqrt3+8=x+x\sqrt3\Rightarrow x=\dfrac{4(\sqrt3+2)}{\sqrt3+1}=\dfrac{4(\sqrt3+2)(\sqrt3-1)}{2}=2(1+\sqrt3)$