Question

(x+1)(6x-7)-(6x-8)(x+1)

Answer 1

6$x^{2}$-7x+6x-7-6$x^{2}$-6x+8x+8=
se reduce 6$x^{2}$ cu 6$x^{2}$, 6x cu 6 x si ne ramane:
x+1 =0 de aici reiese ca x=-1

Answer 2

(x+1)(6x-7)-(6x-8)(x+1)=

(6x²-7x+6x-7)-(6x²+6x-8x-8)=

(6x²-x-7)-(6x²-2x-8)=

6x²-x-7-6x²+2x+8=

x+1