Question

{x+1 supra 2+y+3 supra 4=2 {x-1 supra 3+3-y supra 6 =1​

Answer 1

Răspuns:

x = 2; y = -1

Explicație pas cu pas:

sistem:

$\left \{ {{\frac{x + 1}{2} + \frac{y + 3}{4} = 2} \atop {\frac{x - 1}{3} + \frac{3 - y}{6} = 1}} \right.$

$\left \{ {{2(x + 1) + (y + 3) = 8} \atop {2(x - 1) + (3 - y) = 6}} \right.$

$\left \{ {{2x + 2 + y + 3 = 8} \atop {2x - 2 + 3 - y = 6}} \right.$

$\left \{ {{2x + y = 3} \atop {2x - y = 5}} \right.$

$4x = 8 = > x = 2 \\ y = 3 - 2 \times 2 = 3 - 4 \\ = > y = - 1$