Question

(x+1)(x+2)=56
va rog!

Answer 1

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Answer 2

(x+1)(x+2)=56
$x^{2}$+2x+x+2=56
$x^{2}$+3x-54=0
Δ=$b^{2}$-4ac
Δ=9+216
Δ=225
$x_{1}, x_{2}$=$\frac{-b \frac{+} \ \sqrt{delta} }{2a}$
=$\frac{-3 \frac{+}. \sqrt{225} }{2}$⇒x1=$\frac{-3+15}{2}$=$\frac{12}{2}$=6
⇒x2=$\frac{-3-15}{2}$=$\frac{-18}{2}$=-9

S-(x1, x2)={6, -9}