Question

(x+1)(x+2)=56
(x:50+30):6-6=0
[2(x+2)5+3(x+2)]7=273

Answer 1

(x+1)(x+2)=56
x²+x+2x+2-56=0
x²+3x-54=0
Δ=9+4x54=9+216=225
x₁=(-3+√225)/2=(-3+15)/2=6
x₂=(-3-√225)/2=(-3-15)/2=9

(x:50+30):6-6=0
x/300+5-6=0
x/300-1=0
x/300=1
x=300


[2(x+2)5+3(x+2)]7=273
10x+20+3x+6=39
13x=13
x=1