Question

x^1024-1 descompuneți in factori​

Answer 1

$x^{1024}-1 =$

$=\left(x^{512}\right)^2-1^2$

$=\left(x^{512}+1\right)\left(x^{512}-1\right)$

$=\left(x^{512}+1\right)\left(x^{256}+1\right)\left(x^{128}+1\right)\left(x^{64}+1\right)\left(x^{32}+1\right)\left(x^{16}+1\right)\left(x^8+1\right)\left(x^4+1\right)\left(x^2+1\right)\left(x+1\right)\left$$(x-1)$

Sper ca te-am ajutat!