Question

x+2^0×(2^1990×2+2^1991+2^1992)=2^1994

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Answer 1

X+2^0×(2^1990×2+2^1991+2^1992)=2^1994
X+1×(2^1991+2^1991+2^1992)=2^1994
X+2^1991(1+1+2^1)=2^1994
X+2^1991×4=2^1994
X+2^1991×2^2=2^1994
X+2^1993=2^1994
x=2^1994-2^1993
x=2^1993(2-2^0)
x=2^1993(2-1)
x=2^1993