Question

(x^2+2)(x+3)-x^2(3x+2)+(3x^2+2)(x+2)-4

Answer 1

Răspuns: $\bf \red{\underline{\underline{x^3 +7x^{2} +4x+6}}}$

Explicație pas cu pas:

$\bf \big(x^2+2 \big) \cdot\big(x+3 \big)-x^2\cdot \big(3x+2 \big)+ \big(3x^2+2 \big) \cdot \big(x+2 \big)-4=$

$\bf x^2\cdot x +x^{2} \cdot 3+2 \cdot x+2\cdot3-x^2\cdot3x-x^2\cdot2 + 3x^2\cdot x+3x^2\cdot2 +2 \cdot x+2\cdot 2-4=$

$\bf x^3 +3x^{2} +2x+6~\underline{-3x^3}-2x^2 ~\underline{+ 3x^3}+6x^2 +2x+\not 4-\not 4=$

$\bf \red{\underline{\underline{x^3 +7x^{2} +4x+6}}}$

==pav38==

Baftă multă !