Question

x^2+2x-3=2radical din 3 ...Pana la = totul e sub radical

Answer 1

[tex]\sqrt{x^2+2x-3}=2\sqrt3|()^2\\ x^2+2x-3=12\\ x^2+2x-15=0\\ x^2+5x-3x-15=0\\ x(x+5)-3(x+5)=0\\ (x+5)(x-3)=0\\ x+5=0=\ \textgreater \ x_1=-5\\ x-3=0=\ \textgreater \ x_2=3[/tex]