Question

(x-3)^2-(x-8)^2=(x√2+1)^2-2x^2+10x

Answer 1

(x-3)²-(x-8)²=(x√2+1)²-2x²+10x
x²-6x+9-x²+16x-64=2x²+2x√2+1-2x²+10x
10x-55=2x√2+10x+1
10x-10x-2x√2-55-1=0
-2x√2-56=0
x=-56/2√2
x=-28/√2
rationalizam numitorul:
x=-28√2/2
x=-14√2