Question

(x+4)^2
(2x+1)^2
(1+y)^2

Answer 1

x^2 + 8x + 16

4x^2 + 4x + 1

1 + 2y + y^2

Answer 2

$(x + 4) {}^{2} = x {}^{2} + 8x + 16 \\ (2x + 1) {}^{2} = 4x {}^{2} + 4x + 1 \\ (1 + y) {}^{2} = y {}^{2} + 2y + 1 \\ \\ \boxed{\large\tt{{(a + b) {}^{2} } = a {}^{2} + 2ab + b {}^{2} }}$