Question

x apartine lui R cu proprietatea :modul de x+2mai mic sau egal decat radical din 2

Answer 1

$|x+2| \leq \sqrt{2} \\ x+2 \leq \sqrt{2} \\ x \leq \sqrt{2} -2 \\ x+2 \geq - \sqrt{2} \\ x \geq - \sqrt{2} -2 \\ - \sqrt{2} -2 \leq x \leq \sqrt{2} -2 \\ x \in [- \sqrt{2} -2, \sqrt{2} -2]$