Question

X la a 2 - 2x la a 2 supra xla a2- 2x -3 > 0
Delta?
X1 si x2?

Answer 1

x²-$\frac{2 x^{2} }{ x^{2} } -2x-3\ \textgreater \ 0$
x²-2-2x-3>0
x²-2x-5>0
Δ=4+20=24
$x_{1} = \frac{2+ \sqrt{24} }{2} =1+ \sqrt{6}$
$x_{2} = \frac{2- 2\sqrt{6} }{2} =1- \sqrt{6}$